Hard
Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays.
The overall run time complexity should be O(log (m+n)).
Example 1:
Input: nums1 = [1,3], nums2 = [2]
Output: 2.00000
Explanation: merged array = [1,2,3] and median is 2.
Example 2:
Input: nums1 = [1,2], nums2 = [3,4]
Output: 2.50000
Explanation: merged array = [1,2,3,4] and median is (2 + 3) / 2 = 2.5.
Example 3:
Input: nums1 = [0,0], nums2 = [0,0]
Output: 0.00000
Example 4:
Input: nums1 = [], nums2 = [1]
Output: 1.00000
Example 5:
Input: nums1 = [2], nums2 = []
Output: 2.00000
Constraints:
nums1.length == mnums2.length == n0 <= m <= 10000 <= n <= 10001 <= m + n <= 2000-106 <= nums1[i], nums2[i] <= 106# @param {Integer[]} nums1
# @param {Integer[]} nums2
# @return {Float}
def find_median_sorted_arrays(nums1, nums2)
combined = nums1.concat(nums2)
combined = combined.sort
var4 = 0
if combined.length.odd?
var1 = ((combined.length).div(2))
result = combined[var1]
end
if combined.length.even?
var2 = ((combined.length).div(2))
var3 = (var2) - 1
var4 = (combined[var2]) + (combined[var3])
result = var4 / (2.to_f)
end
result
end