LeetCode-in-Ruby.github.io

4. Median of Two Sorted Arrays

Hard

Given two sorted arrays nums1 and nums2 of size m and n respectively, return the median of the two sorted arrays.

The overall run time complexity should be O(log (m+n)).

Example 1:

Input: nums1 = [1,3], nums2 = [2]

Output: 2.00000

Explanation: merged array = [1,2,3] and median is 2.

Example 2:

Input: nums1 = [1,2], nums2 = [3,4]

Output: 2.50000

Explanation: merged array = [1,2,3,4] and median is (2 + 3) / 2 = 2.5.

Example 3:

Input: nums1 = [0,0], nums2 = [0,0]

Output: 0.00000

Example 4:

Input: nums1 = [], nums2 = [1]

Output: 1.00000

Example 5:

Input: nums1 = [2], nums2 = []

Output: 2.00000

Constraints:

• nums1.length == m
• nums2.length == n
• 0 <= m <= 1000
• 0 <= n <= 1000
• 1 <= m + n <= 2000
• -106 <= nums1[i], nums2[i] <= 106

Solution

# @param {Integer[]} nums1
# @param {Integer[]} nums2
# @return {Float}
def find_median_sorted_arrays(nums1, nums2)
  combined = nums1.concat(nums2)
  combined = combined.sort
  var4 = 0
  if combined.length.odd?
    var1 = ((combined.length).div(2))
    result = combined[var1]
  end
  if combined.length.even?
    var2 = ((combined.length).div(2))
    var3 = (var2) - 1
    var4 = (combined[var2]) + (combined[var3])
    result = var4 / (2.to_f)
  end
  result
end

This site is open source. Improve this page.